Inside an oven, the process that takes place is the convection of air (heat). In this process, the coolest air that are present at the bottom of the oven gets heated up, due to which it becomes warm and lighter, and eventually rises up towards the upper portion of the oven. As these warm air rises, it again cools and subsequently sinks to the bottom.

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These air is again heated and the cycle continues, thereby forms convection cells that allows the food items to get warm inside the oven.

Thus, the coldest air is found always at the bottom of an oven due to its higher density.


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Y_Kistochka <10>5 months ago
4 0

bsci-ch.org:

At the bottom

Explanation:

Air is a fluid. When a fluid is heated, such as in the oven, it undergoes convection: the part of the fluid which is heated more becomes less dense than the rest of the fluid (because the molecules move faster, so the separation between them increases), so it moves on top of the fluid, while the colder parts of the fluid, being more dense, move on bottom. Then the colder parts of the fluid are also heated, and they move on top, and this process continues: we say that a convective current is created.

As we just described, therefore, the colder parts of the air remain at the bottom, since they are more dense than the hotter air.

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In a Heating and Cooling Curve, what is occurring during the flat portions of the curve when the temperature is constant, and wh
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bsci-ch.org:

examining the bsci-ch.orgs the correct one is B.

Explanation:

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* energizes it is used to increase the temperature of the particles,

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Red blood cells can be modeled as spheres of 6.53 μm diameter with −2.55×10−12 C excess charge uniformly distributed over the su
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Complete Question

Red blood cells can be modeled as spheres of 6.53 μm diameter with −2.55×10−12 C excess charge uniformly distributed over the surface. Find the electric field at the following locations, with radially outward defined as the positive direction and radially inward defined as the negative direction. The permittivity of free space ????0 is 8.85×10−12 C/(V⋅m). What is the electric field

E⃗ 1 inside the cell at a distance of 3.05 μm from the center?

E⃗ 2 Just inside the surface of the cell

E⃗ 3 Just outside the surface of the cell

E⃗ 4 At a point outside the cell 3.05 μm from the surface

bsci-ch.org:

E⃗ 1

0 V/m

E⃗ 2

0 V/m

E⃗ 3

*

E⃗ 4

*

Explanation:

From the question we are told that

The diameter is

*

The charge is

*

The permittivity of free space is

*

The distance considered is

*

Generally the electric field inside the cell at a distance of 3.05 μm from the center is

0 V/m

This because there is no electric field felt inside the cell according Gauss the cell is taken as a point charge

Generally the electric field just inside the surface of the cell is 0 V/m

This because there is no electric field felt inside the cell according Gauss the cell is taken as a point charge

Generally the electric field just outside the cell is mathematically represented as

*

Here

*
is the coulomb constant with value

*

r is the radius of the sphere which is mathematically as

*

*
^2 }" alt="E_3 = frac 9*10^9 * <3.265 *10^-6 >^2 " align="absmiddle" class="latex-formula">

*

Generally the electric field at a point outside the cell 3.05 μm from the surface is mathematically represented as

*

Here R is mathematically represented as

*

=>

*

So

*
^2 }" alt="E_4 = frac-2.55 *10^-12 < 6.315 *10^-6 >^2 " align="absmiddle" class="latex-formula">