Everybody enjoys the smell and also taste that freshly-baked bread. The is light and fluffy as a an outcome of the action of yeast on sugar. The yeast converts the street to carbon dioxide, which in ~ high temperatures reasons the dough come expand. The end result is an enjoyable treat, particularly when extended with melted butter.
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Charles"s Law
French physicist Jacques Charles (1746-1823) learned the result of temperature ~ above the volume the a gas at continuous pressure. Charles"s Law states that the volume the a offered mass of gas varies straight with the absolute temperature of the gas once pressure is maintained constant. The absolute temperature is temperature measured v the Kelvin scale. The Kelvin scale need to be used due to the fact that zero ~ above the Kelvin scale synchronizes to a complete stopof molecular motion.

Mathematically, the direct relationship the Charles"s Law can be represented by the adhering to equation:
\<\fracVT = k\>
As with Boyle"s Law, \(k\) is constant only because that a given gas sample. The table below shows temperature and volume data for a collection amount of gas in ~ a continuous pressure. The 3rd column is the constant for this particular data collection and is constantly equal come the volume separated by the Kelvin temperature.
50 | 20 | 0.40 |
100 | 40 | 0.40 |
150 | 60 | 0.40 |
200 | 80 | 0.40 |
300 | 120 | 0.40 |
500 | 200 | 0.40 |
1000 | 400 | 0.40 |
When this data is graphed, the an outcome is a straight line, indicative the a direct relationship, shown in the number below.

Given:
Given:T1 = -27oC and V1 = 34.8 L
V2 = 25.0 L
Find: T2 = ? K
K = -27oC + 273
Plan the problem.
1. Convert the initial temperature come Kelvin
2. Rearrange the equation algebraically to resolve for \(T_2\).
\
Cancel units and also calculate.
1. −67°C + 273 = 206 K
2. Instead of the known quantities into the equation and solve.
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