### 1:5=x/15

This encounters adding, subtracting and also finding the least typical multiple.

You are watching: What is 1/5 of 15

## Step by action Solution

### Rearrange:

Rearrange the equation by individually what is to the best of the equal authorize from both sides of the equation : 1/5-(x/15)=0## Step by step solution :

## Step 1 :

x simplify —— 15Equation at the finish of action 1 : 1 x — - —— = 0 5 15

## Step 2 :

1 simplify — 5Equation at the finish of step 2 : 1 x — - —— = 0 5 15## Step 3 :

Calculating the Least usual Multiple :3.1 discover the Least usual Multiple The left denominator is : 5 The best denominator is : 15Number that times every prime factorappears in the administrate of:PrimeFactorLeftDenominatorRightDenominatorL.C.M = MaxLeft,Right5 | 1 | 1 | 1 |

3 | 0 | 1 | 1 |

Product the allPrime Factors | 5 | 15 | 15 |

Least usual Multiple: 15

Calculating multipliers :3.2 calculate multipliers for the two fractions denote the Least common Multiple by L.C.M represent the Left Multiplier through Left_M signify the best Multiplier through Right_M denote the Left Deniminator by L_Deno denote the best Multiplier through R_DenoLeft_M=L.C.M/L_Deno=3Right_M=L.C.M/R_Deno=1

Making equivalent Fractions :3.3 Rewrite the two fractions into indistinguishable fractionsTwo fountain are called equivalent if they have the exact same numeric value. For instance : 1/2 and 2/4 room equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are identical as well. To calculation equivalent fraction , multiply the numerator of every fraction, through its corresponding Multiplier.

L. Mult. • L. Num. 3 —————————————————— = —— L.C.M 15 R. Mult. • R.

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Num. X —————————————————— = —— L.C.M 15Adding fractions that have a common denominator :3.4 adding up the two equivalent fractions include the two indistinguishable fractions i m sorry now have actually a usual denominatorCombine the molecule together, put the amount or difference over the typical denominator then reduce to lowest terms if possible:

3 - (x) 3 - x ——————— = ————— 15 15 Equation at the end of step 3 : 3 - x ————— = 0 15

## Step 4 :

When a portion equals zero :4.1 once a fraction equals zero ...Where a fraction equals zero, that is numerator, the part which is above the fraction line, need to equal zero.Now,to remove the denominator, Tiger multiplys both sides of the equation through the denominator.Here"s how:3-x ——— • 15 = 0 • 15 15 Now, on the left hand side, the 15 cancels out the denominator, while, top top the ideal hand side, zero time anything is still zero.The equation now takes the shape:3-x=0

Solving a single Variable Equation:4.2Solve:-x+3 = 0Subtract 3 native both political parties of the equation:-x = -3 main point both political parties of the equation by (-1) : x = 3