How many kind of molecules of hydrogen are developed in the adhering to reaction: Solid sodium reacts violently through water, producing heat, hydrogen gas and also sodium hydroxide. 48.7 g of sodium are added to water. The reaction is 2Na + 2H2O --> 2NaOH + H2.
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For sodium reacting via water we have the equation:

2Na (s) + 2H2O -> 2NaOH + H2

One mole of sodium reacts via one mole of water to give one mole of NaOH and fifty percent a mole of H2.

The molar mass of sodium is 22.98

48.7 grams of sodium...


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For sodium reacting through water we have the equation:

2Na (s) + 2H2O -> 2NaOH + H2

One mole of sodium reacts through one mole of water to offer one mole of NaOH and also fifty percent a mole of H2.

The molar mass of sodium is 22.98

48.7 grams of sodium are indistinguishable to 2.11 moles.

As the reaction yields 0.5 mole of H2 per mole of sodium, for 2.11 moles of sodium we have actually 1.06 moles of hydrogen.

One mole of hydrogen has a number of molecules equal to the Avogadro Constant or 6.022* 10^23. 1.06 moles of hydrogen is equal to 6.022* 10^23* 1.06 = 6.38*10^23 molecules.

Thus the number of molecules of hydrogen that 48.7 g of sodium added to water returns is 6.38*10^23.

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