In this tutorial, we will comment on ICl2- lewis structure, molecule geometry, polar or nonpolar, hybridization, etc.

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Name that MoleculeIodine dichloride
Chemical formulaICl2-
Molecular geometry that ICl2-Linear
Electron geometry of ICl2-Trigonal bipyramidal
HybridizationSp³d
NatureNonpolar molecule
Bond angle180°
Total Valence electron in ICl2- lewis structure22

ICl2- lewis structure consists of one iodine atom in ~ the center position whereas 2 chlorine atoms at the surrounding position. There room three lone pairs present on the central atom of ICl2- lewis structure.

Also, the iodine central atom in ICl2- lewis framework violates the octet as it is holding an ext than 8 electron in that is octet shell.

Follow some measures for drawing the lewis framework of ICl2-

1. Count complete valence electron in ICl2-

As the lewis chart is all around filling the valence electron roughly the atoms within a molecule, hence, uncover the complete valence electron in ICl2- molecule.

To counting the valence electron in ICl2- molecule, look at the periodic team of iodine and also chlorine atom in the routine table. Since both iodine and chlorine atom belongs come the same regular group(Group 17), they have actually same valence electrons.


⇒ Total variety of the valence electrons in chlorine atom = 7

⇒ Total variety of the valence electron in iodine atom = 7

∴ Total variety of valence electron available for ICl2- lewis structure = 7 + 7(2) + 1 = 22 valence electrons  <∴ICl2- molecule has actually one iodine and also two chlorine atom v one an unfavorable charge ion>

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2. Uncover the the very least electronegative atom and placed it in ~ center

A less electronegative atom is capable to share much more electrons, hence, the least electronegative atom takes the center position in the lewis diagram.

In the case of the ICl2- molecule, both iodine and chlorine atoms belong to the same routine group however “the electronegativity the an element decrease together we down the group”.

Hence, the iodine atom(2.66) is less electronegative than the chlorine atom(3.16), so, ar iodine at the central position and chlorine spaced evenly about it.

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3. Attach outer atoms to main atom with a solitary bond

In this step, attach both chlorine atoms to the iodine central atom through the assist of a solitary bond.

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Now count the valence electron we used in the above structure. One single bond means two bonded bag of electrons. In the over structure, we usage two solitary bonds because that connecting both side chlorine atom to the iodine main atom.

Therefore, (2 single bond × 2) = 4 valence electron we offered in the above structure native a complete of 22 valence electrons that is accessible for ICl2-.

∴ (22 – 4) = 18 valence electrons

So, we are left v 18 valence electrons more.


4. Ar remaining valence electrons beginning from outer atom first

Now begin placing the continuing to be valence electrons on the external atom(chlorine) to complete their octet i.e. Offering 8 valence electrons in the outer shell of every chlorine atom.

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As you watch in the above figure, we have actually place 6 valence electrons represented as dots approximately both sides chlorine atoms. This is because each chlorine atom already sharing 2 valence electrons v the help of a single bond.

Hence, (one single bond + 6 valence electron together dots) method a total of 8 valence electrons room present around each chlorine atom, hence, both of them completed your octet comfortably.

Now counting the continuing to be valence electrons. In the over structure, (12 valence electrons represented as dots + 2 single bond that consists of 4 electrons) space uses, hence, (12 + 4) = 16 valence electrons are used from total of 22 valence electron available for ICl2-.

∴ (22 – 16) = 6 valence electrons

So, we are left with only 6 valence electrons.


5. Complete central atom octet and also make covalent bond if necessary

We have actually 6 remaining valence electrons and also iodine is the central atom that needs 8 electron in that octet come attains stability. But the iodine atom already has 4 electron in that octet since of two solitary bonds linked to it.

But iodine atom can increase the octet i.e. Having an ext than 8 valence electrons in the outer shell, this is because iodine is below duration two on the periodic table and also have one extra d-orbital obtainable hence, it has actually the capability to expand the octet.

So, placed these 6 staying valence electrons around the iodine central atom. 

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As we view in the above figure, the iodine central atom it s okay 10 electrons(6 stood for as period + 2 solitary bonds) in its external shell and violates the octet rule. However this is no the issue, some elements can violate the octet come gains stability.

So, both atom (iodine and chlorine) completed their octet and also we usage all the total valence electrons the are accessible for illustration the ICl2- lewis structure.

Now we will inspect the security of the above structure with the aid of a formal charge concept.

6. Examine the security with the aid of a formal charge concept


To calculation the formal charge on one atom. Usage the formula given below-

⇒ formal charge = (valence electrons – lone pair electrons – 1/2 bonded pair electrons)

First, counting the formal charge on the chlorine atom.

For chlorine atom:

⇒ Valence electrons of chlorine = 7

⇒ Lone pair electrons on chlorine = 6

⇒ shared pair electrons roughly chlorine(1 solitary bond) = 2

∴ (7 – 6 – 2/2) = 0 formal charge on both political parties chlorine atom.


 For iodine atom

⇒ Valence electrons of iodine = 7

⇒ Lone pair electron on iodine = 6

⇒ shared pair electrons about iodine (2 solitary bonds) = 4

∴ (7 – 6 – 4/2) = -1 formal charge on the iodine main atom.

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The overall formal fee in ICl2- lewis structure is -1 i beg your pardon is same to the fee on the ion(ICl2- molecule has actually one an unfavorable charged ion).

So, the over structure is the many stable, and also lastly, placed the bracket about both sides of the Iodine dichloride lewis structure and show its an adverse charged ion.

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ICl2- lewis structure

The lewis structure for ICl2+

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For ICl2+, we have 20 valence electrons and also the main atom iodine has actually 2 lone pairs and also 2 shared pairs.


The molecular geometry of ICl2- is linear and the electron geometry is trigonal bipyramidal, this is due to the fact that the iodine central atom has actually three lone pairs on one equatorial position and also 2 bonded pairs are attached come it.

As every VSEPR theory, the 3 lone bag on iodine main atom repel each other too as nearby bonded pairs, together a result, the bond pair and also lone pair moved apart from every other and also distorted the shape.

∴ The resultant molecular shape of ICl2- shows up linear.

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We can likewise find the molecular and also electron geometry the ICl2- v the AXE method.

AXE is the an easy generic formula that is based upon bonded atom and lone pair on main atom of a molecule.


AXE notation because that ICl2- molecule:

A denotes the main atom, so, iodine is the main atom, A = IodineX represent the bonded atom to the central atom, together we know, iodine is bonded with two chlorine atoms. Therefore, X = 2E represent the lone pair on the central atom, together per ICl2- lewis structure, iodine has actually three lone pairs. Hence, E = 3

So, the AXE share formula because that the ICl2- molecule i do not care AX2E3.

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Image source

VSEPR theory or graph says, if the central atom of any molecule is attached v two external inspection atoms and also contains a total of three lone pairs then the molecular shape of that molecule is linear, and also electron geometry is trigonal bipyramidal in nature.

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Hybridization the ICl2-

To uncover the hybridization that ICl2-, just determine the steric number of the main atom.

The steric number can be found by the addition of lone pair and bonded atom come a main atom.

∴ Steric number of ICl2- = (Number that bonded atoms to iodine + Lone pair ~ above iodine main atom)

The iodine central atom is bonded v two chlorine atoms and also contains a complete of three lone bag according to the ICl2- lewis structure.

∴ Steric variety of ICl2- = (2 + 3) = 5


Steric numberHybridization
1S
2Sp
3Sp²
4Sp³
5Sp³d
6Sp³d²

So, we get the Sp3d hybridization for ICl2- molecule because that a steric number of five.


A polar molecule has non zero dipole moment and charges are spread asymmetrical everywhere the atoms. In nonpolar molecules, charges are the same, hence, every dipole is canceled out.

So, Is ICl2- polar or nonpolar? ICl2- the molecule is nonpolar in nature since its molecular shape is linear that means dipole the is induced because of the distinction in electronegativity worth of iodine and chlorine atoms are strictly opposite in direction to every other. 

“Also, the three lone bag of electrons on iodine central atom room 120∘ away from each surrounding one, a rotationally-symmetric configuration; so, the lone-pair-bonding-pair repulsions sum to publication out as well.”

The dipoles that space generated along with the bonds(I-Cl) will cancel out to provide a net dipole moment of zero in every directions irrespective of the distinction in electronegativity value in between iodine and chlorine.

Hence, the cancellation that dipole and also symmetric geometry provides the ICl2- nonpolar in nature.


FAQ

What provides the molecular geometry of ICl2- linear?

As per the ICl2- lewis structure, iodine is the main atom that contains 3 lone pairs and 2 bonded pairs attached to it. These electron bag (lone pair + shortcut pair) will repel every other and tried come go far away to minimize the repulsion.

Hence, in every this process, this electron pairs around iodine atom take the position where repulsion between them stays minimum and the final molecular shape of ICl2- appears as linear geometry with bond angle 180°.

Also, the share formula for ICl2- is AX2E3 which indicates the linear molecular shape and also trigonal bipyramidal electron geometry.

Why walk the iodine main atom in ICl2- lewis framework violate the octet and also attains more than 8 electrons?

This is since the iodine atom is below duration two top top the periodic table and has an accessibility to the d-orbital, therefore when it becomes necessary, the iodine atom deserve to open the extra d-orbital and attains much more than 8 electron to complete the octet.

Examples of some aspects that can broaden their octet anytime it’s forced – Sulfur, phosphorus, silicon, and also chlorine, etc.

See more: What Is The Square Root Of 85 In Radical Form ? What Is The Square Root Of 85 In Radical Form

“Elements in the an initial 2 periods of the regular Table do not have access to the d sublevel and also must adhere come the octet rule.”


Summary

The complete valence electron is easily accessible iodine dichloride lewis framework is 22.The steric variety of iodine central atom in the ICl2- the molecule is 5, thus, it develops Sp3d hybridization.The nature of ICl2- is nonpolar since all dipole that generated along the bond will cancel out because of symmetry geometry that it.A complete of 9 lone pairs(3 lone bag on main atom whereas 6 lone pairs on external atoms) and 2 bonded bag are existing in ICl2- lewis structure.The molecular geometry that ICl2- is linear whereas electron geometry is trigonal bipyramidal.The bond edge in ICl2- molecule is 180º.