The picture probably describes my question best.I require to find a way to division a circle into 3 parts of equal area with only 2 present that intersect each other on the outline of the circle.Also I should check, if whatever diameter is between those lines, likewise splits circles v a various diameter into equal parts.And lastly, and probably the most complicated question: just how do I need to calculate the angle between x lines the all intersect in one point, so the the circle is separation into x+1 components with area = 1/(x+1) of the circle?I tried mine best, but couldn"t even discover a solitary answer or the ideal strategy to handle the question...


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geometry one area angle
edited Mar 18 in ~ 20:50

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Given the edge $\theta$, separation by the diameter include $B$, think about the adhering to diagram:


$\overlineBO$ is the line through the center and $\overlineBA$ is the chord cutting turn off the lune whose area we wish to compute.

The area the the circular wedge subtended by $\angle BOA$ is$$\frac\pi-\theta2r^2\tag1$$The area of $\triangle BOA$ is$$\frac12\cdot\overbracer\sin\left(\frac\theta2\right)^\textaltitude\cdot\overbrace2r\cos\left(\frac\theta2\right)^\textbase=\frac\sin(\theta)2r^2\tag2$$Therefore, the area the the lune is $(1)$ minus $(2)$:$$\frac\pi-\theta-\sin(\theta)2r^2\tag3$$To gain the area divided into thirds, we want$$\frac\pi-\theta-\sin(\theta)2r^2=\frac\pi3r^2\tag4$$which method we desire to solve$$\theta+\sin(\theta)=\frac\pi3\tag5$$whose solution have the right to be completed numerically (e.g. Use $M=\frac\pi3$ and also $\varepsilon=-1$ in this answer)$$\theta=0.5362669789888906\tag6$$Giving us


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