A 10.00 -mL sample the vinegar, one aqueous equipment of acetic mountain (HC2H3O2), is titrated v .5073M NaOH, and 17.64 mL is forced to with the equivalence point.

You are watching: How to calculate mass percent of acetic acid in vinegar

What is the molarity of the acetic acid?

If the thickness of the vinegar is 1.006g/cm^3, what is the fixed percent of acetic mountain in the vinegar?

moles the NaOH provided = 0.5073 moles/L x 0.01764 together = 0.008949 moles

moles HC2H3O2 current = 0.008949 mole NaOH x 1 mole HC2H3O2/mole NaOH = 0.008949 mole

Molarity the acetic acid = 0.008949 moles/0.0100 l = 0.8949 M (to 4 far-ranging figures)

10.00 ml vinegar x 1.006 g/ml = 10.06 g vinegar

0.8949 moles acetic acid/liter x 0.0100 liters = 0.008949 moles acetic acid in 10.00 ml the vinegar

0.008949 mole acetic mountain x 60.052 g /mole = 0.5374 g acetic acid

Mass percent acetic acid = 0.5374 g/10.06 g (x100%) = 5.342%

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