You are watching: How many photons are in a 1.20 mj burst of this radiation?
Logged
BorekMr. PHAdministratorDeity Member

Logged
ChemBuddy chemistry calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info, pH-meter.info
sydRegular MemberPosts: 18Mole Snacks: +1/-0
I needed help with one inquiry in a collection of questions. The concerns that are prior to the one i need aid with are: (need aid with bolder ones)One form of sunburn occurs on exposure come UV irradiate of wavelength in the vicinity of 310 nm.a. What is the energy of a photon the this wavelength? E=6.41×10−19 J b. What is the energy of a mole of these photons? E=3.86*10^5 Jc. How many photons space in 1.20 mJ burst of this radiation?? N=? photonsd. These UV photons can break chemistry bonds in her skin to reason sunburn—a type of radiation damage. If the 310 nm radiation provides specifically the power to break an average chemical shortcut in the skin, estimate the average power of these bonds in kJ/mol? median energy= kJ/mol
For c, there is an equation the you deserve to use. It's something choose #photons = ePulse/ePhoton. Both are claimed to it is in measured in J, so you have a an easy conversion to execute first.Good luck v D

XenophiliusInorganic ChemistRegular MemberPosts: 21Mole Snacks: +0/-3Gender: aut viam inveniam aut faciam
See more: How To Say Do You Speak Japanese In Japanese ', How To Say “Do You Speak English” In Japanese
You deserve to use the equation: E=(n*h*(speed of light))/Wavelength. In nanometer the product h*(speed of light) comes out to be practically 1240nm. Hence your prize is merely E/4.