A) On any kind of given line segment, there is specifically one allude that splits it into two different segments.

You are watching: How many lines in the plane are perpendicular bisectors of the segment

B) There room infinitely plenty of bisectors the a segment, every one of which have the right to bisect the segment at different angles.

C) over there is only 1 perpendicular bisector; out of the infinitely many bisectors, only one will intersect in ~ a 90° angle.

D) There room infinitely plenty of in 3 dimensional space. This is since there is a airplane normal to the heat segment (perpendicular to) that goes with the point; there space an infinite number of lines in a plane, so that provides us infinitely many perpendicular bisectors that the segment.

Answer from: Lalagrl

1. A segment can have just 1 midpoint.2. The bisector divides the segment right into two equal parts. Thus, there room infinite number of lines that can be a bisector to the provided segment. The currently differ only in orientation.3. There is only 1 among the bisector that is perpendicular come the segment.4. Over there are boundless perpendicular bisectors in the space.

Answer from: emilymendes546

A. Recognized variables include

Wavelength = 600nm

Theta= 65°

m= 2

B.

d= m x wavelength / sin theta

= 2 * 600*10^-9 /sin 65°

= 1.3*10^-6m

C.

N = 1/d

So N = 1/1.3*10^-6m

=76.9 lines per micro meter

Answer from: mariateamop

Explanation:

It is offered that,

Slit spacing,

We require to discover the lines per mm in the grating. The relation in between the slit spacing and number of lines is given by :

N = 625000 m

or

So, variety of lines per mm is 625. Hence, this is the required solution.

Answer from: cw1242605

zero

Explanation:

because there is no graph come be checked out in the concern :p

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