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You are watching: How many amps does a well pump draw

The residence we to buy is on fine water, but no history on the fine pump was moved to us in the sale...such as horsepower or other specs. I only know it"s 100 feet under to my static water level due to the fact that I tied a fishing weight on fishing line and put it under the well casing until I heard it hit water.On line I see that typical residential fine pumps are around 1- 1.5 horsepower. Through an amp meter I"m getting 12 to run amps after an early stage 25 amp surge. In ~ 240v that amounts to 2,880 watt (or around 3.85 horsepower -at 746w every hp). That seems a small high. Walk anyone know if 12 amps is about normal because that these pumps? I"m wonder if I have actually a worn down pump or acceptable numbers. Thanks
I guess there are no fine pumpers out there responding!

The biggest well pumps I have actually seen space 2 hp in mine area however given that your water table is 100 feet under I would need to assume that the pump is 150-300 feet down and according come what I"ve found online a 1.5 hp pump will certainly pump to 275 feet ( this is because that a utilitech pump ~ above lowes site) and draw 11.5 amps if you have actually a 1.5 horse pump I"d speak you"re an excellent for reference a 1 hp pump will certainly draw about 9.8 amps I"m sure the numbers room different between manufacturers yet hope this assisted you may additionally be may be to uncover info ~ above the well at your county documents office many counties save the information on paper at the very least in mine neck the the woods
thanks for the reply. Ns guess it"s it s okay amp range. I"ll have to examine those records you mentioned and also see what they have on file. Weird why the mathematics for back calculating the horsepower doesn"t come out quite right. Provided there"s 746 watts per horsepower..a pump drawing 12 amps must be: 12amps x 240v = 2880watts / 746w = 3.85hp
. Ns guess this pumps space operating at greater horsepower than their rating.. Unless the 1.5hp is just a static rating,, together in pumping no water

More than likely the rating counts on the pump manufacturer for circumstances a an ext expensive Wayne pump might be closer to two hp plus has actually a much better warranty and longer life expectations needed a utilitech pump indigenous the big box stores is rated closer to its yes, really power yet has a much shorter warranty and also lifespan compare the specs for very same hp pimps indigenous both manufacturers there is a large difference in the lift capability between the two
thanks because that the reply. Ns guess it"s it s okay amp range. I"ll have actually to check those documents you mentioned and see what they have actually on file. Strange why the math for earlier calculating the horsepower doesn"t come out rather right. Provided there"s 746 watt per horsepower..a pump drawing 12 amps should be: 12amps x 240v = 2880watts / 746w = 3.85hp. I guess this pumps are operating at greater horsepower 보다 their rating.. Uneven the 1.5hp is just a revolution rating,, together in pump no water
Your mathematics is wrong carry out to not understanding the power element the motor is operating at. Also you room not acquisition your analysis at the engine so the wiring warmth loss is a element as well. The 3rd an most important item is what is the discharge push an flow GPM at the moment of amperage an voltage measurement?
Once friend know exactly how a device/system, operates, finding the root reason in the occasion chain is easy. Until then, you will constantly be chasing/repairing the effects.

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Hi,Even if the a is one old thread, that in necessary to keep in mind the Kre"s comment: The power factor is a an extremely important worth to know the real power taken by a pack with windings inside. These windings have a characteristic named inductance the modifies the straightforward formula provided by Kanoa50. To correct this formula we have to use a element named power Factor.When we use a DC supply, in a passive circuit (no transistors or electronics), the existing is steady in a very short time. V no voltage variations, no current variations.When an alternate current is used, over there is a continuos sports in the voltage applied (60 times every second) and also of food in the current (Amps) circulating. In the situation of a pure resistive load, the voltage variations are followed by proportional present variations at exactly the very same time. Voltage and current room in phase.When the load contains coils or windings (as in motors or transformers) and are fed through AC, this coils react sending out a voltage in the opposite direction, to reduce the reliable voltage applied. This reaction take away a time so the existing increases a tiny after the voltage raises. The is the present lag with respect to the voltage and also this value in a trigonometric representation develops an angle who cosine is named cos φ (cos Phi)or power factor.This PF varies in a motor or transformer follow to the load applied. The cosine function varies indigenous 0 come 1, however in the common electrical tons it is normal to found values between 0.4 come 0.95 (+or-) and is the element that reduces the Volts x Amps product. At much less load, less power factor. Volts x Amps = obvious power in VA or KVAVolts x Amps x cos φ = actual power watt or KW.In this case, suspect a PF = 0.8Apparent power: 240 V x 12 Amp = 2880 VA or 2.8 KVAReal power: 240 V x 12 Amp x 0.8 = 2304 watts or 2.304 KWBut...This is the actual power soaked up by the motor, yet this engine is no perfect, the dissipates heat, electromagnetic waves, mechanical vibrations, noise etc etc. Every this energy waste comes from our incoming 2304 Watts, so the mechanical calculation in the form of a rotational force used to the pump"s obelisk can"t be the exact same as the intake power. The relationship in between the calculation power and also the input strength is the efficiency and also it will never ever reach the unit (100%).In this case assuming an 80% effectiveness :Input power x Eff. = strength in the shaft2304 watts x 0.8 = 1843 Watts1843 watt / 746 W/Hp= 2.47 HPThis is only an approximation, presume PF and also Eff. This values readjust ,as Kre explains, through the circulation of water (GPM) and also the pressure (PSI). Every pump has actually its own set of curve that determine most that the variables uncovered on it. Regards