A little bit of trained eyeballing can help here. Let me tell you how I saw the bsci-ch.org without any computation.
You are watching: Find the factorization of the polynomial below
Remember that the expansion of a squared binomial is
So, the square of a binomial has the following properties, which you can easily spot:
- It has three terms
- Two of them are perfect squares
- The third is twice the product of the two roots.
Well, in this case we do have three terms, and indeed
So, the bsci-ch.org is
If you want to see some explicit calculations, just use the quadratic formula
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Ede4ka <16>10 months ago
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Hope this helps you!!..
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The common ratio of the sequence is r the sequence is (42, 21, 10.5, 5.25, . . .)
SCORPION-xisa <38>
bsci-ch.org:
Step-by-step explanation:
r = 21/42 = 1/2 ( also 10.5 / 21 = 1/2)
This is a Geometric Sequence with first term 42 and common ratio 1/2.
7 0
11 months ago
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Factorise completely x^3+6x^2+3x-10
natima <27>
bsci-ch.org:Solution
(
−
1
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(
+
2
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(
+
5
)
(
x
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1
)
(
x
+
2
)
(
x
+
5
)
(x−1)(x+2)(x+5)
Step-by-step explanation:
How to solve your problem
3
+
6
2
+
3
−
1
0
x
3
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6
x
2
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3
x
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10
x3+6x2+3x−10
Grouping
1
Find one factor
Factor by grouping
Factor by grouping
Factor by grouping
4 0
1 month ago
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Help me please this should be easy
vichka <17>
bsci-ch.org:
what grade are you in ?
Step-by-step explanation:
3 0
3 months ago
LetX1=5,10,15,20andY1=5,10,15,20,25. Using the formal definition of a func-tion, determine which of the following subsets of
tino4ka555 <31>
bsci-ch.org:
Option b) is the bsci-ch.org
Step-by-step explanation:
A function from X₁ to Y₁ is an object f such that every x in X₁ is uniquely associated with an object f(x) = y in Y₁.
Then
1(b)f=(5,25),(10,5),(15,5),(20,10),(5,25) is the correct bsci-ch.org.
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It follows that
f(5) = 25
f(10) = 5
f(15) = 5
f(20) = 10
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8 months ago
Find the coordinates of the Ortho center of triangle ABC with vertices A(2,6) B (8,6) and C (6,2)
liq <111>
The ortho center is (6,4).
3 0
7 months ago
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