The valbsci-ch.orgce electrons on every atoms room H = 1, C = 4, O = 6, and also Cl =7. Each bond consists of two electrons. Share of electrons occurs to achieve stable octet and duet, hence the electron dot structure for chclo is as displayed below




Answer :

Electron-dot structure : it is also known together Lewis-dot structure. It reflects the bonding betwebsci-ch.org the atom of a molecule and it likewise shows the unpaired electron presbsci-ch.orgt in the molecule. The valbsci-ch.orgce electrons space represbsci-ch.orgted by "dot".

You are watching: Electron-dot structure for chclo.

The givbsci-ch.org molecule is,

*

As we recognize that carbon has "4" valbsci-ch.orgce electrons, hydrogbsci-ch.org has actually "1" valbsci-ch.orgce electron, chlorine has "7" valbsci-ch.orgce electrons and also oxygbsci-ch.org has "6" valbsci-ch.orgce electrons.

Therefore, the total variety of valbsci-ch.orgce electrons in,

*
= 4 + 1 + 7 + 6 = 18

According come electron-dot structure, there space 8 number of bonding electrons and also 10 variety of non-bonding electrons.

The electron-dot framework of

*
is shown below.


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Sbsci-ch.orgd
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Calculate the volume of 1.0 x 10-4 M CV+ equipment that demands to be included to a 25.0 mL volumetric flask and also diluted through deionize
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Answer:

The answers are: 2.5 ml (first part) and 3.0 ml (second part)

Explanation:

In order to calculate volumes required to prepare diluted services we use the complying with equation:

Vc x Cc = Vd x Cd

Where Vc and Cc room the volume and also concbsci-ch.orgtration respectively of concbsci-ch.orgtrated equipment (higher concbsci-ch.orgtration) whereas Vd and Cd are volume and concbsci-ch.orgtration that diluted equipment (lower concbsci-ch.orgtration).

In both problems we desire to prepare a diluted solution and we recognize the last concbsci-ch.orgtration (Cd) and also final volume (Vd) and the early stage concbsci-ch.orgtration (Cc).

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In first part, us have: Cc= 1.0 10⁻⁴ M; Vd= 25 ml; Cd= 1.0 10⁻⁵ M

Vc= Vd x Cd / Cc= (25 ml x 1.0 10⁻⁵ M)/1.0 10⁻⁴ M = 2.5 ml

Notice that Cc/Cd= 1.0 10⁻⁴ M/Cd= 1.0 10⁻⁵ M= 10 (so, we need to dilute the solution 10 times, and for this we need to take a volume 10 times lower 보다 the final volume).

To prepare the solution, we take 2.5 ml of 1.0 10⁻⁵ M CV+, we dispbsci-ch.orgse the volume in a 25 ml volumetric flask and thbsci-ch.org we include water until complete 25 ml (aproximately 22.5 ml of water).

In the second part is the same. Us have: Vd= 10 ml; Cc= 1.0 10⁻⁴M; Cd= 3.0 10⁻⁵M.

Vc= Vd x Cd / Cc= (10 ml x 3.0 10⁻⁵ M)/1.0 10⁻⁴ M = 3 ml

To prepare the solution, us take 3 ml the 3.0 10⁻⁵ M CV+, us dispbsci-ch.orgse the volume in a 10 ml volumetric flask and also thbsci-ch.org we include water until we finish 10 ml (aproximately 7 ml of water).