You are watching: Do diagonals of a parallelogram bisect each other

With the being said, ns was wonder if within parallel the diagonals bisect the angle which the meet.

For instance, please refer to the link, go $overlineAC$ bisect $angle BAD$ and also $angle DCB$?

If they diagonals do undoubtedly bisect the angle which lock meet, can you please, in layman"s terms, present your proof?

Thanks, guys!

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edited may 21 "20 in ~ 10:41

amWhy

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asked Jun 3 "16 in ~ 16:45

RidhwaanRidhwaan

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$egingroup$ Yes but not a common parallelogram, just in a square, rhombus and also kite. $endgroup$

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Jun 3 "16 in ~ 17:11

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The diagonals bisect angles only if the sides are all of equal length.

Proof -

Assume that the diagonals without doubt bisect angles.

Then $angle BCE=angle ECD$ in her diagram.

Also $angle ECD=angle EAB$ due to the fact that $AB | DC$.

So $angle BCE = angle EAB$, hence $ riangle BAC$ is isosceles with $AB=BC$.

Similar arguments also prove equality of various other sides, $BC=CD$ and also $CD=DA$.

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answer Jun 3 "16 in ~ 16:53

KalElKalEl

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Nope that doesn"t...We can prove it making use of congruency triangle.U have the right to see the vertically the contrary angles are equal.Not the diagonal bisect angle

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answered might 15 "19 at 5:11

HEPIN RAJESHBHAI SAVALIYAHEPIN RAJESHBHAI SAVALIYA

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