You are watching: Do diagonals of a parallelogram bisect each other
With the being said, ns was wonder if within parallel the diagonals bisect the angle which the meet.
For instance, please refer to the link, go $overlineAC$ bisect $angle BAD$ and also $angle DCB$?
If they diagonals do undoubtedly bisect the angle which lock meet, can you please, in layman"s terms, present your proof?
edited may 21 "20 in ~ 10:41
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asked Jun 3 "16 in ~ 16:45
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$egingroup$ Yes but not a common parallelogram, just in a square, rhombus and also kite. $endgroup$
Jun 3 "16 in ~ 17:11
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The diagonals bisect angles only if the sides are all of equal length.
Assume that the diagonals without doubt bisect angles.
Then $angle BCE=angle ECD$ in her diagram.
Also $angle ECD=angle EAB$ due to the fact that $AB | DC$.
So $angle BCE = angle EAB$, hence $ riangle BAC$ is isosceles with $AB=BC$.
Similar arguments also prove equality of various other sides, $BC=CD$ and also $CD=DA$.
answer Jun 3 "16 in ~ 16:53
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Nope that doesn"t...We can prove it making use of congruency triangle.U have the right to see the vertically the contrary angles are equal.Not the diagonal bisect angle
answered might 15 "19 at 5:11
HEPIN RAJESHBHAI SAVALIYAHEPIN RAJESHBHAI SAVALIYA
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