JavaScript is disabled. For a better experience, please permit JavaScript in her browser prior to proceeding.

You are watching: Complicated math equation that equals 1

I"m trying to come up v a facility equation that amounts to 53.5x - 2x + x * 7x + 23 * x / 78652x = 53That one is nice lackluster though.I"m looking front to see what the math wizards here have the right to come increase with. I"m trying come come up v a complicated equation that equates to 53. 5x - 2x + x * 7x + 23 * x / 78652 x = 53 that one is nice lackluster though. I"m looking forward to see what the mathematics wizards here deserve to come increase with.
I median one have the right to make this together arbitrarily complicated as friend want. For example, also the coefficents in your above equation deserve to be complex amazingly. (displaystyle 2=sum_n=0^inftyleft(frac12 ight)^n=sum_n=0^inftye^nlnleft(frac12 ight)=sum_n=0^inftysum_ell=0^inftyfracleft(nlnleft(frac12 ight) ight)^ellell!cdots) advertisement infinitum I"m trying to come up v a complicated equation that equals 53. 5x - 2x + x * 7x + 23 * x / 78652 x = 53 that one is nice lackluster though. I"m looking front to see what the math wizards here can come increase with.
Unless you clearly state precisely what mathematical background deserve to be drawn upon, this question is just going to reason confusion and waste time. Note:
Posting this question in Pre-algebra and Algebra means a lift severly limit what you could otherwise have in mind.

See more: 1998 Jeep Grand Cherokee Fuel Filter Location, Does A 1998 Jeep Cherokee Have A Fuel Filter

I should"ve composed it differently.I"m wanting come say: Y + X = 535x - 2x + x * 7x + 23 * x / 78652Something favor that.I guess: v shouldn"t have left the question so open. I"m looking for something that is algebra and also can be addressed in speak 10 minute by someone v a great grasp that algebra.
So we offered with: .(displaystyle x :=:53)Subtract 3 native both sides: .(displaystyle x - 3 :=:50)Double both sides: .(displaystyle 2(x-3) :=:100)Subtract 9 native both sides: .(displaystyle 2(x-3) - 9 :=:91)Divide through 7: .(displaystyle oxedfrac2(x-3) = 97 :=:13)~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~If (displaystyle x = 5) have the right to be among the roots of the equation . . .Start with: .(displaystyle x :=:53)Subtract 3: .(displaystyle x - 3 :=:50)Divide by 5: .(displaystyle fracx-33 :=:10)Cube both sides: .(displaystyle left(fracx-35 ight)^3 :=:10^3 quadRightarrowquad frac(x-3)^3125 :=:1000). . (displaystyle x^3 - 9x^2 + 27x - 27 :=:125,!000 quadRightarrowquadoxed x^3 - 9x^2 + 27x - 125,!027 :=:0 )