Homework explain

Balance the complying with equation and also write the correspondingionic and net ionic equation (if appropriate):CH_3COOH _(aq)+ KOH _(aq) ightarrow

Homework Equations

None as much as i know.

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The attempt at a Solution

I wrote:CH_3COOH _(aq)+ KOH _(aq) ightarrow CH_3COOK _(aq) + H_2O _(l)But this is the wrong answer.I don"t recognize why K^+ does not type a compound v CH_3COO^-. Have the right to anyone phone call what principle or law/theorem controls what compounds type and what compounds execute not form? Why is K^+ a spectator ion in this reaction?
Your reaction equation is OK, it simply doesn"t answer the question - you to be asked to create ionic and net ionic reactions. I m sorry of the compounds current in the reaction will be completely dissociated?Note: style indices in her formulae with and also tags, not v LaTeX. And also state of matter should be normal text, ~ above the very same level as the formula (so liquified potassium acetate is CH3COOK(aq) - rendered together CH3COOK(aq)).
Your reaction equation is OK, it just doesn"t answer the question - you to be asked to write ionic and net ionic reactions. I m sorry of the compounds current in the reaction will be totally dissociated?Note: layout indices in your formulae with and also tags, not with LaTeX. And also state of issue should be common text, top top the very same level together the formula (so liquified potassium acetate is CH3COOK(aq) - rendered together CH3COOK(aq)).

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So mine initial heat of thinking was:Molecular Equation:CH3COOH (aq)+ KOH (aq) → CH3COOK (aq) + H2O (l)Ionic Equation:CH3COO- (aq) + H+ (aq) + K+ (aq) + OH- (aq) → CH3COO- + K+ + H2O (l)Net Ionic Equation: H+ (aq) + OH- (aq) → H2O (l)This is incorrect.But ns reasoned that CH3COO- is a weak mountain so all of the things in the textbook around not dissociating 100% have to come into play here.Therefore,Molecular Equation:CH3COOH (aq)+ KOH (aq) → CH3COOK (aq) + H2O (l)Ionic Equation:CH3COOH (aq) + K+ (aq) + OH- (aq) → CH3COO- +K+ + H2O (l)Net Ionic Equation: CH3COOH (aq) + OH- (aq) → CH3COO- + H2O (l)That is correct according come the answer in the text.How come CH3COO- and also K+ carry out not type a link though? Is there anyway to calculate or know why? Is it since CH3COOH is no dissociated 100% in solution? (it is a weak acid.)Thanks for the aid with composing the equations.